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2x^2-51x+50=0
a = 2; b = -51; c = +50;
Δ = b2-4ac
Δ = -512-4·2·50
Δ = 2201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51)-\sqrt{2201}}{2*2}=\frac{51-\sqrt{2201}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51)+\sqrt{2201}}{2*2}=\frac{51+\sqrt{2201}}{4} $
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